已知tan2A=3,则sinA/(cosA+sinA)+cosA/(cosA-sinA)=
人气:450 ℃ 时间:2020-02-05 23:16:22
解答
sinA/(cosA+sinA)+cosA/(cosA-sinA)=(sinA/cosA)/(cosA/cosA+sinA/cosA)+(cosA/cosA)/(cosA/cosA-sinA/cosA)=tanA/(1+tanA)+1/(1-tanA)=tanA(1-tanA)/(1+tanA)(1-tanA)+(1+tanA)/(1-tanA)(1+tanA)=[tanA(1-tanA)+(1+...
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