∫1/[(2-3x)(2x+1)] dx=∫6/[(4-6x)(6x+3)] dx=∫6/7[1/(4-6x)+1/(6x+3)] dx=1/7[∫1/(6x+3) d(6x+3)+∫1/(4-6x)d(4-6x)]=1/7ln(6x+3)-ln(4-6x)+C=1/7ln[(6x+3)/(4-6x)]+C