函数f(x)=sin^2x+sin2x+3cos^2x,求函数f(x)的周期,要过程_数学解答

函数f(x)=sin^2x+sin2x+3cos^2x,求函数f(x)的周期,要过程

人气：483 ℃　时间：2019-08-20 16:53:51

解答

f(x)=sin^2x+sin2x+3cos^2x
=1+sin2x+2cos^2x
=2+sin2x+cos2x
=2+√2sin(2x+π/4)
∴T=2π/2=π
答：周期为π