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(sint+cost)/(cost-sint)怎么算的,等于tan(t+π/4)
人气:372 ℃ 时间:2020-02-04 07:01:40
解答
(sint + cost) / (cost-sint)
= [(sint + cost)/√2] / [(cost - sint)/√2]
= (sint cosπ/4 + cost sinπ/4) / (cost cosπ/4 - sint sinπ/4)
= sin(t+π/4) / cos(t+π/4)
= tan(t+π/4)
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