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设u=(e^xy)(cos(x+y^2)),求du
人气:297 ℃ 时间:2020-07-10 09:19:13
解答
对x偏导du/dx=ye^xy(cos(x+y^2))+e^xy(-sin(x+y^2)) 偏导的那个a打不出来对y偏导du/dy=xe^xy(cos(x+y^2))+e^xy(-sin(x+y^2))2ydu={ye^xy(cos(x+y^2))+e^xy(-sin(x+y^2))}dx+{xe^xy(cos(x+y^2))+e^xy(-sin(x+y^2))2y}...
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