∫cos^2θdθ=?
积分区间为[0,2π]
有点转不过弯了,
人气:461 ℃ 时间:2020-04-30 17:12:23
解答
∫(0,2π)cos^2θdθ=∫(0,2π)[(1+cos(2θ))/2]dθ
=(1/2)[θ+sin(2θ)/2]|(0,2π)
=(1/2)(2π)
=π.
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