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先化简,再求值:1/3(-3ax^-ax^+3)-[-ax^-2/3ax-1].其中a=2.x=3
人气:118 ℃ 时间:2020-06-14 10:37:04
解答
1/3(-3ax^-ax+3)-[-ax^-2/3ax-1]
=-ax²-1/3ax+1+ax²+2/3ax+1
=1/3ax+2 其中a=2.x=3
=1/3*2*3+2
=2+2
=4
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