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已知x的平方-8x-3=0,求(x-i)(x-3)(x-5)(x-7)的值
人气:290 ℃ 时间:2020-03-29 07:23:05
解答
x²-8x-3=0
x²-8x=3
(x-1)(x-3)(x-5)(x-7)
=(x-1)(x-7)(x-3)(x-5)
=(x²-8x+7)(x²-8x+15)
=(3+7)(3+15)
=10*18
=180
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