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计算 lim(x->0)(1+1/2x)^x
人气:294 ℃ 时间:2020-05-14 09:51:49
解答
解法一:原式=lim(x->0){(1+1/2x)^[(2/x)(x²/2)]}
=[lim(x->0){(1+1/2x)^(2/x)]^[lim(x->0)(x²/2)]
=e^0 (应用重要极限lim(x->0)[(1+x)^(1/x)]=e)
=1;
解法二:原式=lim(x->0){e^[xln(1+x/2)]}
=e^{lim(x->0)[xln(1+x/2)]
=e^(0*ln1)
=e^0
=1.
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