√(2+√3)=√[(4+2√3)/2]
=√[(3+2√3+1)/2]
=√[(√3+1)^2/2]
=(√3+1)*√(1/2)
同理√(2-√3)=(√3-1)*√(1/2)
所以真数=(√3+1)*√(1/2)+(√3-1)*√(1/2)
=2√3*√(1/2)
=√6
=6^(1/2)
所以原式=1/2