设等差数列{an}的前n项和为Sn,已知(a5-1)3+2009(a5-1)=1,(a2005-1)3+2009(a2005-1)=-1,则下列结论中正确的是( )
A. S2009=2009,a2005<a5
B. S2009=2009,a2005>a5
C. S2009=-2009,a2005≤a5
D. S2009=-2009,a2005≥a5
人气:404 ℃ 时间:2020-04-16 16:31:58
解答
∵等差数列{an}的前n项和为Sn,(a5-1)3+2009(a5-1)=1,∴(a5-1)[(a5−1)2+2009]=1,∵(a5−1)2+2009>0,∴a5-1>0,即:a5>1.∵(a2005-1)3+2009(a2005-1)=-1,∴(a2005-1)[(a2005−1)2+2009]=-1,∵(...
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