x³+x²-(4x+4)=(x³+x²)-(4x+4)
=x²(x+1)-4(x+1)
=(x²-4)(x+1)
=(x-2)(x+2)(x+1)第一部括号里面的不要变号吗x³+x²-4x-4=(x³-4x)+(x²-4)=x(x²-4)+(x²-4)=(x+1)(x²-4)=(x+1)(x+2)(x-2)不客气！