> 数学 >
lim(x趋向0)arctanx-sinx/x^3
人气:450 ℃ 时间:2019-09-09 17:42:44
解答
lim(x→0) (arctanx - sinx)/x³,洛必达法则= lim(x→0) [1/(1 + x²) - cosx]/(3x²)= (1/3)lim(x→0) (1 - cosx - x²cosx)/(x² + x⁴),洛必达法则= (1/3)(1/2)lim(x→0) (sinx - 2xcos...
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版