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lim(x趋向0)(x-arctanx)/(x-arcsinx)=?
人气:306 ℃ 时间:2019-10-17 03:08:53
解答
根据罗比达法则,分子分母同时求导lim(x趋向0)(x-arctanx)/(x-arcsinx)=lim(x趋向0)[1-1/(1+x^2)]/(1-1/根号(1-x^2))=lim(x趋向0)[x^2/(1+x^2)]/(-x^2/[(1+根号(1-x^2)(根号(1-x^2)]=-lim(x趋向0){(1+根...
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