设f(x)是定义域为R,最小正周期为3π/2的周期函数,当-π/2
人气:228 ℃ 时间:2020-01-24 16:05:46
解答
f(-15π/4)=f(-18π/4 +3π/4)=f[-3•(3π/2)+3π/4]=f(3π/4)=sin3π/4=sin(π-π/4)=sin(π/4)=√2/2
推荐
猜你喜欢
- 36,120和90的最大公约数
- A:Here______a list of sll the clubs. B:What______do you______to join? A:I want to join the_____cl
- 英语翻译
- ____goodweatheritistoday!
- Do you know where she is working now?
- 如图,矩形A’BC’O’是矩形OABC(边OA在X轴正半轴,边OC在Y轴正半周上)饶B逆时针旋转得到的.O’点在X轴的正半轴上,B点的坐标为(1,3)(1)如果二次函数Y=AX^2+BX+C(A≠0 )的图象经过O,O’ 两点且图象顶点 M
- 一桶油连桶重160千克,倒出一半油后,连桶重90千克,问:这桶油原来重多少千克?桶重多少千克?
- 若ax²;+bx+c>0的解为(2,4),则cx²;+bx+a