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因式分解:2x^4-x^3+2x^2+1 x^4-3x^2+4x-3 x^4+x^3+2x^2-x+3 a^2(b-c)+b^2(c-a)+c^2(a-b)
人气:473 ℃ 时间:2020-06-06 17:06:06
解答
(1)、2X^4-X^3+2X^2+1
=2X^4-2X^3+2X^2+x^3+1
=2x^2(x^2-x+1)+(x+1)(x^2-x+1)
=(2x^2+(x+1))(x^2-x-1)
=(2x^2+x+1) (x^2-x+1)
(2)、x^4-3x^2+4x-3
=x^4-3x^2+3x+x-3
=x^4-x^3+x^2+x^3-x^2+x-3x^2+3x-3
=(x^2 + x - 3)(x^2 - x + 1)
(3)、x^4+x^3+2x^2-x+3
=x^4+x^3+2x^2+2x-2x-x+3
=x^3(x+1)+2x(x+1)-3(x+1)
=(x+1)(x^3+2x-3)
(4)、a^2(b-c)+b^2(c-a)+c^2(a-b)
=a^2b-a^2c+b^2c-ab^2+ac^2-bc^2
=a^2b-ab^2+b^2c-a^2c+ac^2-bc^2
=(a+c)(a-c)b-(a+b)(a-b)c-(b+c)(b-c)a
=(a - b) (b - c)(a - c)
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