a^2+b^2+c^2+4-ab-3b-2c = (a^2 -ab +1/4 b^2)+( 3/4 b^2 -3b +3) +(c^2-2c+1) = (a-b/2)^2 + (根号3*b/2-根号3)^2+(c-1)^2<=0
所以 a = b/2 = 1,b = 2,c = 1
原式 = 200+9b(我想是你打错了）+c = 200+18+1 = 219