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求证(1-sinα)/cosα=tan(π/4-α/2)
人气:317 ℃ 时间:2020-04-15 19:54:40
解答
左边=(cosα/2-sinα/2)^2/[cos^2(α/2)-sin^2(α/2)]
=(cosα/2-sinα/2)/(cosα/2+sinα/2)
=(1-tanα/2)/(1+tanα/2)
=(tanπ/4-tanα/2)/(1+tanπ/4tanα/2)
=tan(π/4-α/2)
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