由已知可得：a²-2014a+1=0那么：a²-2013=a-1,a²+1=2014a,a²-2014a=-1,a²-a+1=2013a所以：a²-2013a + (a²+1)分之2014=a-1+ (2014a)分之2014=a-1 + (a分之1)=a分之(a²-a+1)=a...