f(x)为R上的奇函数,f(x)=-f(-x)令x=0得：f(0)=-f(-0)即f(0)=-f(0),2f(0)=0,所以f(0)=0.已知x>0时,f(x)=x^2-2x+2当x0f(-x)=(-x)^2-2(-x)+2=x^2+2x+2因为f(x)为奇函数,f(x)=-f(-x)所以f(x)=-x^2-2x-2（当x0)f(x)=0,x=0...