已知定义域为R的函数F(X)=-2X+A/2X+1是奇函数,求A值
求A值
判断并证明该函数在定义域R的单调性
人气:295 ℃ 时间:2019-11-06 19:33:08
解答
F(X)=-2X+A/2X+1是奇函数
F(-x)=-F(x)
F(-x)+F(x)=0
F(0)=0
-1+A=0
A=1
F(X)=-2^X+1/2^X+1
=-1+2/2^X+1
2^X单调递增,F(x)单调递减,通分化简,易证
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