y对x求导,得y'=6x²-1所以在点(1,1)处的切线斜率k = y'|x=1 = 6-1 = 5法线斜率k' = -1/k = -0.2在点(-1,-1)处的切线斜率k = y'|x=-1 = 6-1 = 5由点斜式y= kx+b,代入(-1,-1)和k=5可得b=4,故切线方程为y=5x+4法线...