log(c+b)a+log(c-b)a
=
1 |
loga(c+b) |
1 |
loga(c−b) |
=
loga(c+b)+loga(c−b) |
loga(c+b)•loga(c−b) |
=
loga(c2−b2) |
loga(c+b)•loga(c−b) |
=
logaa2 |
loga(c+b)•loga(c−b) |
=log(c+b)a•log(c-b)a.
∴原等式成立.
1 |
loga(c+b) |
1 |
loga(c−b) |
loga(c+b)+loga(c−b) |
loga(c+b)•loga(c−b) |
loga(c2−b2) |
loga(c+b)•loga(c−b) |
logaa2 |
loga(c+b)•loga(c−b) |