若不等式ax的平方+x+a小于0的解集为空集,则实数a的取值范围
没括号的
人气:125 ℃ 时间:2019-09-25 22:14:18
解答
解集为空,
即不等式ax^2+x+a0,△≤0
△=1-4a^2≤0
4a^2≥1
a^2≥1/4
a≥1/2或a≤-1/2(舍去)
所以a的范围是a≥1/2
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