证明：过点A作AM⊥BE于M,AN⊥CD于N∵等边△ABD、等边△ACE∴AB＝AD,AC＝AE,∠BAD＝∠CAE＝60∵∠BAE＝∠CAE+∠BAC,∠DAC＝∠BAD+∠BAC∴∠BAE＝∠DAC∴△ABE≌△ADC （SAS）∴BE＝CD,S△ABE＝S△ADC∵AM⊥BE,AN⊥CD...