用x^3表示“x的三次方”.|a-b|^3 + |c-a|^2 = 1,又因为abc都是整数,说明只有两种情况：(1)|a-b| = 0; |c-a| = 1 ==> a=b; |c-a| = 1(2)|a-b| = 1; |c-a| = 0 ==> a=c; |a-b| = 1那么(1)|a-c| + |c-b| + |b-a| = |a-c...