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a大于0,解关于x的方程1+log2真数(2lga—x)除以log2真数x=2logx真数2
人气:472 ℃ 时间:2020-05-30 06:06:03
解答
1+log2真数(2lga—x)除以log2真数x=2logx真数2logx(x)+log2[(2lga-x)]/log2(x)=logx(4)logx(x)+logx(2lga-x)=logx(4)logx[x(2lga-x)]=logx(4)x(2lga-x)=4x²-2lga*x+4=0用求根公式解得x=[2lga±根号(4(lga)&su...
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