①当x>=1时
f(x)=2x^2+(x-1)^2=2x^2+x^2+1-2x
=3x^2-2x+1
=3(x^2-2/3x+(2/6)^2-(2/6)^2)+1
=3(x-2/6)^2+2/3
因为x>=1
所以最小值为
f(1)=2
②当x