x>=-1,f(x)=2x^2+(x+1)^2=3x^2+2x+1=3(x+1/3)^2+2/3,x=-1/3,fmin=2/3,
x大神,我发错了,是f(x)=2x的平方+(x-1)|x-1|哦，那这样：x>=1, f(x)=2x^2+(x-1)^2=3x^2-2x+1=3(x-1/3)^2+2/3,fmin=f(1)=2x<1,f(x)=2x^2-(x-1)^2=x^2+2x-1=(x+1)^2-2,fmin=f(-1)=-2所以最小值为-2