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函数f(x)={[根号(1-x^2)]/(X-3)} -m有零点的充要条件?
人气:226 ℃ 时间:2019-10-17 06:06:21
解答
f(x)=√(1-x^2)/(X-3) -m有零点√(1-x^2)/(X-3) =m有实数解√(1-x^2)=m(x-3)有实数解y=√(1-x^2)与y=m(x-3)图象有交点函数y=√(1-x^2)(-1≤x≤1,0≤y≤1)x^2+y^2=1 (-1≤x≤1,0≤y≤1)图象为圆x^2+y^2=1的上半部分(...
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