求曲线的渐近线 y=3+2x^2+1/(x-1)^2
Y呢?
人气:256 ℃ 时间:2020-04-01 05:14:36
解答
y=3+2x^2+1/(x-1)^2
定义域 中 x≠1
渐近线 k=limf(x)/x=[3+2x^2+1/(x-1)^2]/x=3/x+2x+1/[x(x-1)^2]= 无穷 x趋近于无穷的时候
所以曲线有垂直于x轴的渐近线 就是 x=1
推荐
猜你喜欢
- what are you doing this weekend?选什么?
- 若sinx≥根号3/2,求x范围
- Looks up at the man that she turned
- 设数列{an{bn}{cn},已知a1=4,b1=3,c1=5,a(n+1)=an,b(n+1)=(an+cn)/2,c(n+1)=(an+bn)/2.求数列{cn-bn}的通项公式(2)求证:对任意n属于N*,bn+cn为定值
- it's tall and strong,but still it has no flowers.
- 甲乙两人从AB两地相向而行,相遇时,甲所行路程为乙的2倍多1.5千米,乙所行路程为甲路程的5/2,两地相距?
- 己知直线ax+4y-2=0与直线2x-5y+b=0互相垂直于点(1,c),求a,b,c,的值
- What will he do if he spend all the money?改错