已知直线l的方程为xsina-根号3y+2=0,则l的倾斜角的取值范围是
人气:217 ℃ 时间:2019-08-22 20:52:38
解答
xsina-√3y+2=0
y=√3*sina *x/3+2√3/3
设l的倾斜角为α
tanα=√3*sina /3
-1≤sina≤1
则 -√3/3≤tanα≤√3/3
则 {α|5π/6≤α≤π} ∪{α| 0≤α≤π/6}
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