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初二关于幂的运算的数学题
1.-1/3*a^2*x^4-(2ax^2)^4
2.2(y^3)^2*y^3-(3y^3)^2+(5y)^2*y^7
人气:260 ℃ 时间:2020-05-16 06:37:17
解答
1.-1/3*a^2*x^4-(2ax^2)^4
=-1/3a^2x^4-16a^4x^8
=a^2x^4(-1/3-16a^2x^4)
2.2(y^3)^2*y^3-(3y^3)^2+(5y)^2*y^7
=2y^9-9y^6+25y^9
=27y^9-9y^6
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