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已知x/3=y=z/2≠0,则2x^2-2y^2+5z^2/xy+yz+zx
人气:163 ℃ 时间:2020-08-24 00:59:02
解答
已知x/3=y=z/2≠0,∴x=3y,x²=9y²;z=2y,z²=4y².(2x²-2y²+5z²)/(xy+yz+zx)=(18y²-2y²+20y²)/(3y²+2y²+6y²)=(36y²)/(11y²)=36/11=3又3/1...
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