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sin(x^2)/sin^2x 求导
人气:396 ℃ 时间:2020-04-14 16:01:09
解答
y = sin(x^2) / (sinx )^2
y ' = 2x cos(x^2) / (sinx )^2 + sin(x^2) * (-sin2x)/(sinx)^3
= 【 2x cos(x^2) (sinx) + sin(x^2) * (-sin2x) 】 /(sinx)^3
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