f(x)=4sin(x-π/3)cosx+√3
=4sinxcosπ/3cosx-4cosxsinπ/3cosx+√3
=sin2x-√3(cos2x+1)+√3
=sin2x-√3cos2x
=2(1/2sin2x-√3/2cos2x)
=2sin(2x-π/3)
T=2π/2=π