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[(-a²b^n)³×(a^n-1×b²)³]^5
人气:255 ℃ 时间:2020-09-11 14:29:30
解答
[(-a²b^n)³×(a^n-1×b²)³]^5
=[(-a^6b^3n×a^(3n-3)b^6]^5
=[(-a^(3n+3)b^(3n+6)]^5
=-a^(15n+15)b^(15n+30)
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