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用开方法解方程(给详细过程) (1) 3(x-2)^2=0
(2) 3(x-1)^2=27
(3) 5(x-3)^2-125=0
(4) 3(y-1)^2=75
人气:273 ℃ 时间:2020-02-05 23:08:08
解答
3(x-2)²=0
(x-2)²=0
x-2=0
∴x=2

3(x-1)²=27
(x-1)²=9
x-1=±3
∴X1=4
X2=-2

5(x-3)²-125=0
(x-3)²=25
x-3=±5
∴X1=8
X2=-2

3(y-1)²=75
(y-1)²=25
y-1=±5
∴y1=6
y2=-4(2x 5)^2-1=04x^2-4x 1=5(2x -5)²-1=0(2x-5)²=12x-5=±12x=5±1∴x1=3 x2=1 4x²-4x+ 1=5(2x-1)²=52x-1=±√52x=1±√5∴x=(1±√5)/2没什么
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