y=根号1+sinx+根号1-sinx的化简?
它的值域多少 怎么求
人气:216 ℃ 时间:2020-01-28 15:32:54
解答
y=根号1+sinx+根号1-sinx
=根号(1+2sin1/2xcos1/2x)+根号(1-2sin1/2xcos1/2x)
=根号(sin1/2x+cos1/2x)^2+根号(sin1/2x-cos1/2x)
=|sin1/2x+cos1/2x|+|sin1/2x-cos1/2x|
(去掉绝对值要看x的大小)
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