求x,y的值 4x+3y=17 和 √(x-2)²+(y-3)²=20
人气:457 ℃ 时间:2020-02-05 05:55:48
解答
∵ (2,3)在直线 4x+3y-17=0上,
直线的斜率是-4/3
设直线的参数方程为 x=2+3t,y=3-4t
代入和 √(x-2)²+(y-3)²=20
9t²+16t²=400
∴ 25t²=400
∴ t²=16
∴ t=4或t=-4
(1)t=4时,
x=14,y=-13
(2)t=-4时,
x=-12,y=19
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