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f(x)=(e的2x次方-1)/kx,x>0;f(x)=1-x,x<=0,在x=0处连续,求k
人气:248 ℃ 时间:2020-03-28 13:43:04
解答
lim(x→0-) f(x)
=lim(x→0-) (1-x)=1
lim(x→0+) f(x)
=lim(x→0+) (e^2x-1)/(kx)
=lim(x→0+) 2x/(kx)
=2/k
=1
k=2
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