设y=(sin2x)^x,求dy/dx
最好过程能具体点啦
人气:153 ℃ 时间:2020-01-27 04:55:29
解答
y= (sin(2x))^x
lny = xln(sin(2x))
(1/y)y' = 2xcos(2x)/sin(2x) +ln(sin(2x))
y' =[2xcos(2x)/sin(2x) +ln(sin(2x))] (sin(2x))^x
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