设曲线f(x)D [0.1]上可导,且y=f(sin2x)+f(cos2x)求dy/dx
人气：258 ℃ 时间：2019-08-20 10:34:08
解答
复合函数求导公式：d(u(v)) / dx = u'(v)*v'dy/dx = f'(sin2x)*(sin2x)'+f'(cos2x)*(cos2x)'= f'(sin2x)*cos2x*(2x)'+f'(cos2x)*(-sin2x)*(2x)'= f'(sin2x)*cos2x*2+f'(cos2x)*(-sin2x)*2= 2f'(sin2x)*cos2x - 2f'(c...
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