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已知x/(x^2-4x-1)=-1/3,求x^4+2x+1/x^5的值
人气:369 ℃ 时间:2020-03-24 03:19:28
解答
x/(x^2-4x-1)=-1/3
x^2-4x-1=-3x
x^2-x-1=0
x^2=x+1
x^4=x^2+2x+1=x+1+2x+1=3x+2
x^5=x^4*x=(3x+2)x=3x^2+2x=3(x+1)+2x=5x+3
(x^4+2x+1)/x^5
=(3x+2+2x+1)/(5x+3)
=(5x+3)/(5x+3)
=1
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