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解方程组2x^2-2xy+x+y-4=0 3x^2-3xy+x-2=0
人气:403 ℃ 时间:2020-06-05 14:02:16
解答
2x^2-2xy+x+y-4=0,①3x^2-3xy+x-2=0.②①*3-②*2,x+3y-8=0,x=8-3y,③代入②,3(8-3y)(8-4y)+8-3y-2=0,12y^2-57y+66=0,y1=11/4,y2=2,分别代入③,x1=-1/4,x2=2.∴{x1=-1/4,{y1=11/4;{x2=2,{y2=2.
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