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1/(3*5)+1/(5*7)+1/(7*9)+…1/(103*105)
分子都是1,括号内的两数是分母!
人气:216 ℃ 时间:2020-03-23 23:38:14
解答
1/(3*5)+1/(5*7)+1/(7*9)+…1/(103*105)
=1/2*(1/3-1/5+1/5-1/7+1/7+...-1/103+1/103-1/105)
=1/2*(1/3-1/105)
=17/105
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