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xy-y²分之y√x+x√y-x√x-y√y分之x+√xy+y 注:√是根号,这题答案是√y分之1
人气:112 ℃ 时间:2019-11-21 02:36:13
解答
原式=(y√x+x√y)/(xy-y²)-(x+√xy+y)/(x√x-y√y)=(y√x+x√y)/[y(x-y)]-[(x+√xy+y)(x√x+y√y)]/[(x√x-y√y)(x√x+y√y)]=(y√x+x√y)/[y(x-y)]-(x²√x+xy√y+x²√y+y²√x+xy√x+y²√y...
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