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已知3x^2-x=1,求6x^3+7x^2-5x+2001的值
人气:205 ℃ 时间:2019-12-13 13:51:34
解答
3x^2-x=1
6x^3+7x^2-5x+2001
=6x^3-2x^2+9x^2-5x+2001
=2x(3x^2-x)+9x^2-5x+2001
=2x+9x^2-5x+2001
=9x^2-3x+2001
=3(3x^2-1)+2001
=3*1+2001
=2004
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