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在等差数列{an}中,证明
a1+a2+…+a2n−1
2n−1
=an(n∈N*)
人气:168 ℃ 时间:2020-02-05 12:49:58
解答
证明:在等差数列{an}中,
a1+a2+…+a2n−1
2n−1

=
2n−1
2
(a1+a2n−1
1
2n−1

=
1
2
(a1+a2n-1
=
1
2
(an+an
=an
a1+a2+…+a2n−1
2n−1
=an
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