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化简f(x)=2倍根号3SinxCosx+2Cosx的平方-1
人气:325 ℃ 时间:2020-05-01 14:12:06
解答
f(x)=√3sin2x+cos2x
=2(sin2x*√3/2+cos2x*1/2)
=2(sinxcosπ/6+cos2xsinπ/6)
=2sin(2x+π/6)
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